x1dan x2 akar persamaan log2x+log x-6=0 maka nilai x1x2
Matematika
anana12341
Pertanyaan
x1dan x2 akar persamaan log2x+log x-6=0 maka nilai x1x2
1 Jawaban
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1. Jawaban Anonyme
log² x + log x - 6 = 0
log x1 + log x2 = -b/a = -1/1 = -1
log x1 . x2 = -1
x1 . x2 = 10^-1 = 1/10 = 0,1 ✓