1.20 derajat fahrenheit=......celsius 2.20 derajat fahrenheit=.......kelvin 3.20 derajat Fahrenheit=.....reamur Kak tolong jawab dengan caanya

1. 20 °F =........°C
tc = 5/9 tf - 32
= 5/9 × 20 - 32
= 100 - 32 / 9
= 8,66°C
2. 20 °F =.......°K
tk = ( 20°F - 32) × 5/9 + 273,15
= -20 + 237,15/ 3
= 9,983 °K
3. 20 °F =........°R
tr = 4/9 × tf - 32
= 4/9 × 20 - 32
= - 16/3
= 5,33 °R