Persamaan Garis (no 16)

Jawab :

16. melalui titik (0,0) , dan (3,-2)

m = y2 - y1/ x2 - x1 = (-2) - 0/ 3 - 0 = -2/3 (D)

[tex](x1 ,y1) = (0,0) \\ (x2 ,y2) = (3, - 2) \\ \\ \frac{x - x1}{x2 - x1} = \frac{y - y1}{y2 - y1} \\ \frac{x - 0}{3 - 0} = \frac{y - 0}{ - 2 - 0} \\ \frac{x}{3} = \frac{y}{ - 2} \\ 3y = - 2x \: \: ( \div 3) \\ y = - \frac{ 2}{3} x[/tex]

Jadi, jawabannya D.