Matematika

Pertanyaan

f¹(1) jika f(t) = sin(t²-3t-1)

1 Jawaban

  • f(t) = sin (t^2-3t-1)
    f'(t) = cos (t^2-3t-1).(2t-3)
    f'(t) = (2t-3) cos (t^2-3t-1)
    f'(1) = (2.1 -3) cos (1^2-3.1-1)
    = - cos (-3)

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