berapa hasil no 1,2,3 kaka?? tolong pakai rumus yaa... bsok d kumpul...please...

bismillahirrohmanirrohim
nomor 1
= ^3√^4√a^12b^8
=^12 √a^6b^4(kuadratkan nilai sebelumnya maka jadi nilai ini)

nomor 2
=(a-b)(a+2b)
=a^2 + 2ab - ab - 2b^2
=a^2 + ab - 2b^2

nomor 3
(√5 - √2)(√5+√5)
10 - (10√5)
10 - 2√5

[tex] 1. \: \sqrt[3]{ \sqrt[4]{ \sqrt{ {a}^{12} {b}^{8} } } } \\ = \sqrt[3]{ \sqrt[4]{ {({a}^{12} {b}^{8})}^{ \frac{1}{2} } } } \\ = \sqrt[3]{ \sqrt[4]{ {({a}^{6} {b}^{4})} } } \\ = \sqrt[3]{ {( {a}^{6} {b}^{4}) }^{ \frac{1}{4} } } \\ = \sqrt[3]{ {a}^{ \frac{6}{4} }b } \\ = { ( {a}^{ \frac{6}{4} }b) }^{ \frac{1}{3} } \\ = {a}^{ \frac{1}{2} } {b}^{ \frac{1}{3} } [/tex]
[tex]2. \: (a - b)(a + 2b) \\ = {a}^{2} + 2ab - ab - 2 {b}^{2} \\ = {a}^{2} + ab - 2 {b}^{2} [/tex]
[tex]3. \: ( \sqrt{5} - \sqrt{2} )( \sqrt{5} + \sqrt{5} ) \\ = 5 + 5 - \sqrt{10} - \sqrt{10} \\ = 10 - 2 \sqrt{10} \\ atau \\ = 2(5 - \sqrt{10} )[/tex]
Maaf kalo salah, semoga membantu