Matematika

Pertanyaan

2 log 2 (x +1) - 4 2log (x+1) + 3 =0

1 Jawaban

  • ²log² (x +1) - 4 ²log (x + 1) + 3 = 0
    misal ²log (x + 1) = a

    a² - 4a + 3 = 0
    (a - 1)(a - 3) = 0
    a = 1 atau a = 3

    ²log (x + 1) = 1
    ²log (x + 1) = ²log 2
    x + 1 = 2
    x = 1

    ²log (x + 1) = 3
    ²log (x + 1) = ²log 8
    x + 1 = 8
    x = 7

    Jadi, x = 1 atau x = 7

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