himpunan penyelesaian| 2× - 1 = | 4× + 3 |

[tex]|2x-1|=|4x+3|\\(2x-1)^2=(4x+3)^2\\(2x-1)^2-(4x+3)^2=0\\ \left[(2x-1)+(4x+3)\right]\times[(2x-1)-(4x+3)]=0 \\ (6x+2)(-2x-4)=0\\-4(3x+1)(x+2)=0\\x_1=-\frac{1}{3},x_2=-2[/tex]