Matematika

Pertanyaan

bisa tolong jawab soal ini..? no 3,5,6,7,8,9,12
bisa tolong jawab soal ini..? no 3,5,6,7,8,9,12

1 Jawaban

  • 7) 3x²-(p+2)x + (p-5)= 0

    Kebalikan x1 = 1/x2

    x1.x2 = 1
    c/a = 1
    c/3 = 1
    c = 3
    p-5 = 3
    p = 8

    9)x²-6x-2= 0
    α+β = 6
    αβ = -2

    x1+x2 = (α-2)+(β-2)
    = α+β -4
    = 6-4
    = 2

    x1.x2 = (α-2)(β-2)
    = αβ-2(α+β)+4
    = -2-2.6 + 4
    = -10

    pk : x² - (x1+x2) x + x1.x2 = 0
    x² - 2x - 10 = 0


    12)x²+4x + (a-4)
    x1.x2 = a-4
    1.3. = a-4
    a = 3+4
    = 7