jika 3 log 6 = p maka nilai 25 log 30 adalah

3log 6 = p
log 6/ log 3 = p
(log 3 + log 2)/log 3 = p
log 3/log 3 + log 2/log 3 = p
1 + 3log 2 = p
3log 2 = p -1.
25log 30 = log 30/log 25
log 30/log (100/4)
log (3×10)/log 100 - log 4
( log 3 + log 10 ) / log 10^2 - log 2^2
= ( log 3 + 1)/( 2 - 2.log 2). beri bilangan pokok baru 2, maka.
= (2log 3 + 1) / (2- 2.2log 2)
= { 1/(p-1)+1 } / (2 - 2)
= { 1 + p -1)/(p-1) / 0
= { p / (p-1) }/ 0