tulis himpunan penyelesaian persamaan nilai mutlak I2x-8I-12=0

I2x-8I-12 = 0
|2x-8| = 12

☞ 2x - 8 = 12
2x = 12 + 8
2x = 20
x = 20/2
x = 10
☞ -(2x - 8) = 12
-2x + 8 = 12
-2x = 12-8
-2x = 4
x = 4/-2
x = -2

HP : { -2 , 10 }