²log 24+²log 8-²log 6=

[tex] {}^{2} log(24) + {}^{2} log(8) - {}^{2} log(6) \\ = {}^{2} log( \frac{24 \times 8}{6} ) \\ = {}^{2} log(4 \times 8) \\ = {}^{2} log(32) \\ = {}^{2} log(2 {}^{5} ) \\ = 5. {}^{2} log(2) \\ = 5 \times 1 \\ = 5[/tex]

semoga membantu
Maaf kalo salah ya