akar akar persamaan ³log²x-3³logx+³log1 adalah x1 dan x2 a.12 b.10 c.3 d.8 .e.24

Jawab :

³log² x - 3 . ³log x + ³log 1 = 0
³log² x - 3 . ³log x + 0 = 0
³log² x - 3 . ³log x = 0

³log x1 + ³log x2 = -b/a = -(-3)/1 = 3
³log x1x2 = 3
x1 . x2 = 3³ = 27