Jawabkan yaa beserta cara nya :)

[tex] { {}^{3} log }^{2} x - 3 {}^{3} logx + 2 = {}^{3} log1 \\ misal \: {}^{3} logx = y \\ {y}^{2} - 3y + 2 = {}^{3} log1 \\ {y}^{2} - 3y + 2 = 0 \\ (y - 2)(y - 1) \\ y = 2 \: atau \: y = 1 \\ \\ y_{1} = 2 \\ {}^{3} logx = 2 \\ x = {3}^{2} \\ x_{1} = 9 \\ \\ y_{2} = 1 \\ {}^{3} logx = 1 \\ x_{2} = 3 \\ \\ x_{1} + x_{2} = 9 + 3 = 12[/tex]
A