diketahui fungsi f(x)=1-2x dan (g 0 f )=4 x2 - 6x + 3 tentukan : a. g(x) b. (f o g)(3)

Jawab :

f(x) = 1 - 2x

g(f(x)) = 4x² - 6x + 3
g(1 - 2x) = (1 - 2x)² + (1 - 2x) + 1
g(x) = x² + x + 1 ✔

(fog)(3)
= f(3² + 3 + 1)
= f(13)
= 1 - 2.13
= 1 - 26
= -25 ✔