suatu fungsi ditentukan dengan rumus f(x)=ax + b. jika f(3)=11,dan f(2)=8,tentukanlah nilai f(-2) tolong dijawab pake jalan yaa..please

f(3)=11
3a+b=11

f(2)=8
2a+b=8

11=3a+b
8=2a+b
______ _
3=a

2×3+b=8
6+b=8
b=2

f(-2)=a×-2+b=3×(-2)+2=-6+2=-4

f(3) = 11 = 3a + b
f(2) = 8 = 2a + b

3a + b = 11
2a + b = 8
Dikurang
a = 3

3x + b = 11
3(3) + b = 11
9 + b = 11
b = 11 - 9 = 2

f(-2) = ?
= ax + b
= 3(-2) + 2
= -6 + 2 = -4