Pada fungsi g(x) = ax + b jika g(2) = 6 dan g (-2) = -2 nilai a dan b adalan?

g(x) = ax + b

g(2) = a2 + b
6 = 2a + b

g(-2) = a(-2) + b
-2 = -2a + b

eliminasi
2a + b = 6
-2a + b = -2
dijumlahkan
0 + 2b = 4
2b = 4
b = 4/2
b = 2

substitusi
2a + b = 6
2a + 2 = 6
2a = 6 - 2
2a = 4
a = 4/2
a = 2

maka nilai a = 2 dan nilai b = 2