Matematika

Pertanyaan

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1 Jawaban

  • Kelas 10 Matematika
    Bab Logaritma

    ^ = pangkat

    ^3log x = a

    ^3log² x - 3 . ^3log x + 2 = ^3log 1
    a² - 3a + 2 = 0
    (a - 2) (a - 1) = 0
    a - 2 = 0
    a = 2

    a - 1 = 0
    a = 1

    ^3log x = 2
    x = 3^2
    x = 9

    ^3log x = 1
    x = 3^1
    x = 3

    Syarat:
    x > 0

    x1 + x2 = 3 + 9
    x1 + x2 = 12