Nilai dari 2log 2+ 2log 4+ 2log 8

[tex] {}^{2} log(2) + {}^{2} log(4) + {}^{2} log(8) \\ = {}^{2} log(64) = {}^{2} log(2 {}^{6} ) \\ = 6. {}^{2} log_{}(2) \\ = 6 \times 1 \\ = 6[/tex]