please,pakai caranya y #matematika wjib kls10
Matematika
Febyy252
Pertanyaan
please,pakai caranya y
#matematika wjib kls10
#matematika wjib kls10
1 Jawaban
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1. Jawaban AnugerahRamot
1.]
6|2x - 3| = 54
|2x - 3| = 9
2x - 3 = 9 atau 2x - 3 = -9
2x = 12 atau 2x = -6
x = 6 atau x = -3
2.]
| 2x - 3 / 4 - x | ≥ 3
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[tex] \frac{2x-3}{4-x} \geq 3 \\
\frac{2x - 3}{4-x} - 3 \geq 0 \\
\frac{2x - 3 - 3(4 - x)}{4 - x} \geq 0 \\
\frac{5x-15}{-(x - 4)} \geq 0 \\
\frac{5x - 15}{x - 4} \leq 0 [/tex]
3 ≤ x < 4 ... (i)
____________________________
[tex] \frac{2x-3}{4-x} \leq -3 \\
\frac{2x - 3}{4-x} + 3 \leq 0 \\
\frac{2x-3+3(4-x)}{4-x} \leq 0 \\
\frac{-x+9}{4-x} \leq 0 \\
\frac{-(x - 9)}{-(x - 4)} \leq 0 \\
\frac{x - 9}{x-4} \leq 0 [/tex]
4 < x ≤ 9
HP : {x | 3 ≤ x < 4 atau 4 < x ≤ 9}
atau
HP : {x | 3 ≤ x ≤ 9 , x ≠ 4}