jawab yah,pakai cranya

Persamaan Eksponen
[tex] (2x^2 - 3x - 3)^{x + 2} = (2x^2-3x-3)^{2x + 5} [/tex]

1.)
x + 2 = 2x + 5
-x = 3
x = -3

2.)
2x² - 3x - 3 = 1
2x² - 3x - 4 = 0
a = 2 , b = -3 , c = -4

D = b² - 4ac
D = (-3)² - 4(2)(-4) = 41

[tex] x_{1,2} = \frac{-b \pm \sqrt{D}}{2a} \\
x_{1,2} = \frac{3 \pm \sqrt{41}}{4} \\
x = \frac{3 + \sqrt{41}}{4} \ atau \ x = \frac{3 - \sqrt{41}}{4} [/tex]

3.)
2x² - 3x - 3 = 0
a = 2 , b = -3 , c = -3

D = b² - 4ac
D = (-3)² - 4(2)(-3) = 33

[tex] x_{1,2} = \frac{-b \pm \sqrt{D}}{2a} \\
x_{1,2} = \frac{3 \pm \sqrt{33}}{4} \\
x = \frac{3 + \sqrt{33}}{4} \ atau \ x = \frac{3 - \sqrt{33}}{4} [/tex]

Jawaban : B