^27log9 + ^2log3. log 4 basis akar tiga _______________________________ ^3log2 - ^3log 18
Matematika
tamaramelisaputri
Pertanyaan
^27log9 + ^2log3. log 4 basis akar tiga _______________________________ ^3log2 - ^3log 18
1 Jawaban
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1. Jawaban Anonyme
jawab
misal
P= ²⁷lo9 + ²log 3. (√3)'log 4
P = ³^³log 3² + ²log 3. 2. ³log 2²
P = 2/3 + 4
Q = ³log 2 - ³log 18
Q = ³log (2/18) = ³log 1/9 = ³log 3⁻²
Q = - 2
P/Q = (2/3 + 4)/(-2)
P/Q = (2 +12)/(-6)
P/Q = (14)/ -6
P/Q = - 2 ¹/₃