Log 2 basis 7 = a , log3 basis 2 = b, maka log 14 basis 6 adalah,Tolong dibantu ya kak
Matematika
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Pertanyaan
Log 2 basis 7 = a , log3 basis 2 = b, maka log 14 basis 6 adalah,Tolong dibantu ya kak
2 Jawaban
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1. Jawaban dnnyz07
^7 log 2 = a --> ²log 7 = 1/a
² log 3 = b
^6 log 14
= ( ²log 14 ) / (² log 6)
= (²log (7x2)) / (²log(3x2))
= (²log 7 + ²log 2) / (²log 3 + ²log 2)
=( (1/a) + 1) / (b + 1)
= ( (a + 1)/a)) / (b + 1)
= ((a + 1)/ a ) x (1/(b + 1))
= (a + 1) / (ab + a) -
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