tolong dong beserta caranya

Fungsi invers
Kelas X

[tex] f^{-1} (x - 1) = \frac{4 - 3x}{x - 2} \\
Maka \\
f( \frac{4 - 3x}{x - 2} ) = x - 1 [/tex]

[tex] Andaikata \ \frac{4 - 3x}{x - 2} = -5 [/tex]
↔ 4 - 3x = -5x + 10
↔ 2x = 6
↔ x = 3

Maka
f(-5) = 3 - 1 = 2

[D]

f^-1 (x-1) = (1-3(x-1)) / (x-1-1)
f^-1 (x) = (1-3x) / x-1
x = (1-3y) / (y-1)
xy - x = 1-3y
xy+3y= 1+x
y(x+3) = 1+x
y= (1+x) / (x+3)

F(-5) = (1-5) / (-5+3)
= -4 / -2
= 2