[tex]^{4} log( \frac{1}{32} ) + ^{3} log(243) - ^{2 ^{125}}log(625) [/tex] Nilai diatas adalah.. (pakai caranya ya, terimakasih) a. [tex] - \frac{1}{6} [/tex] b

[tex] {}^{4} log( \frac{1}{32} ) + {}^{3} log(243) - 2. {}^{125} log(625) \\ = {}^{2 {}^{2} } log(2 {}^{ - 5} ) + {}^{3} log(3 {}^{5} ) - 2. {}^{5 {}^{3} } log_{}(5 {}^{4} ) \\ = - \frac{5}{2} + 5 - 2 \times \frac{4}{3} \\ = - \frac{5}{2} + 5 - \frac{8}{3} \\ = - \frac{1}{6} [/tex]
Jawaban = (A)