Nilai dari 2log4+32log3.3log4

2 log 4 + 32 log 3 × 3 log 4
2 log ( 2^2 ) × 32 log ( 3^1 ) + 3 log ( 2^2 )
2 × 1 + 2 = 4

LogaRitMa

(a^n)'log (b^m) = (m/n) . a'log b

•••
2'log 4 + 32'log 3 . 3'log 4
= 2'log 2² + (2^5)'log 4²
= 2 + 2/5
= 2 2/5
= 12/5 ✔