Tolong di Bantu jawab yaaa,

2sin^2.x-4√3sin x cos x +2cos^2.x + 1 = 0
2sin^2.x+ 2cos^2.x - 2√3(2sin x cos x) +1 = 0
2(sin^2.x + cos^2.x) -2√3(sin 2x) + 1 = 0
2.1 - 2√3 sin 2x + 1 = 0
2+1 -2√3 sin 2x = 0
-2√3 sin 2x = -3
sin 2x = -3/-2√3
sin 2x = 3/2√3
sin 2x = 3√3/6
sin 2x = (1/2)√3
sin 2x = sin 1/3π, 2/3π
2x = 1/3π + 2kπ
x = 1/6π + kπ
untuk k = 0. => x = 1/6π
untuk k = 1. => x = 7/6π
untuk k = 2. => x = 13/6π ( diluar interval)
2x = 2/3π + 2kπ
x = 1/3π + kπ
untuk k = 0. => x = 1/3π
untuk k = 1, => x = 4/3π
untuk k = 2. => x = 7/3π ( diluar interval)
HP = { 1/6π, 1/3π, 7/6π, 4/3π }