bila (x+5y)^2= a x^2+b xy+c y^. tentukan nilai (c-b) :

MAPEL = MATEMATIKA
KELAS = 8
BAB = OPERASI HITUNG ALJABAR

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {(x + 5y)}^{2} = a {x}^{2} + bxy + c {y}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: (x + 5y)(x + 5y) = a {x}^{2} + bxy + c {y}^{2} \\ \:{x}^{2} + 5xy + 5xy + 25 {y}^{2} = a {x}^{2} + bxy + c {y}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: {x}^{2} + 10xy + 25 {y}^{2} = a {x}^{2} + bxy + c {y}^{2} \\ [/tex]
jadi nilai
a = 1
b = 10
c = 25

nilai C - B
= 25 - 10
= 15

semoga membantu