tentukan [tex]y = ln(x {}^{2} - \: 1) [/tex] tooloonng iya kerjain

jawab

y = ln(x² -1) 

u = x² -1
du/dx = 2x

y = ln u
dy/du = 1/u

dy/dx = dy/du. du/dx
y'= 1/u . (2x)
y' = (2x)/(x² + 1

tuRUNan

y = ln (x² - 1)

y' = dln (x² - 1) /d(x² - 1) × d(x² - 1)/dx
y' = 1/(x² - 1) . 2x
y' = 2x / (x² - 1). ✔