tolong y besok di kumpul sekalian pakai cara
Matematika
herin7
Pertanyaan
tolong y besok di kumpul sekalian pakai cara
2 Jawaban
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1. Jawaban royinda
37. (x+3)(x+3). atau (x+3)² B
nb: 3+3 = 6 dan 3×3 = 9
38. dicari akar dari masing2 bilng.dahulu
√25= 5 dan √16 = 4
jika hasil nya kuadrat maka salah satu hrus - jadi (5x+4)(5x-4) C
39. carannya sama dengan penjumlahan pecahan bjasa
y2+4y /(y)²(y) - 3y²/(y²)(y) = 4-2y²/y³ D
40. K=(2×panjang)+(2×lebar)
={2.(2x+3)} + {2.(x-5)}
= 4x + 6. + 2x-10
= 6x - 4 C
semoga membantu.. -
2. Jawaban algebralover
No. 37
x² + 6x + 9 = (x + 3)(x + 3) = (x + 3)²............Jawaban (B)
No. 38
a² - b² = (a - b)(a + b)
25x² - 16 = (5x)² - (4)² ........... a = 5x ; b = 4
= (5x - 4)(5x + 4) = (5x + 4)(5x - 4)...........Jawaban (C)
No. 39
[tex]= \frac{y+4}{y^{2}} - \frac{3}{y} \\ \\ \\ = \frac{y(y+4)-3y^{2}}{y^{3}} \\ \\ \\ = \frac{y^{2}+4y-3y^{2}}{y^{3}} = \frac{4y-2y^{2}}{y^{3}} \\ \\ \\ = \frac{4y-2y^{2}}{y^{3}} = \frac{y(4-2y)}{y^{3}} \\ \\ \\ = \frac{4-2y}{y^{2}} ........... Jawaban\ (D)[/tex]
No. 40
Keliling = 2 × (panjang + lebar)
Keliling = 2 × ((2x + 3)+(x - 5))
Keliling = 2 × (3x - 2)
Keliling = (6x - 4) cm ..................Jawaban (C)