f(x)=ax+b f(-3)= -15 f(3)= 9, berapakah nilai dari f(-2) + f(2)

f(-3)=a(-3) + b = -15
= -3a + b = -15
f(3)= a(3) + b = 9
= 3a +b = 9

-3a + b = -15
3a + b = 9
___________ - (dikurangi)
-6a = -24
a= 4
3a + b = 9
3(4) + b = 9
12 + b = 9
b = -3
f(x) = ax + b = 4x - 3

f(-2)= 4(-2) -3 = -8 -3 = -11
f(2)= 4(2) - 3 = 8 - 3 = 5

f(-2) + f(2)= -11 + 5 = -6

maaf kalau salah :)

Kelas : 8 SMP
Mapel : Matematika
Bab : Relasi dan Fungsi

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