apabila 3log5=a,2log3=b,maka nilai 6log10=.......

3log 5 = a dan 2log 3 = b,
6log 10 = log 10/log 6
=( log 5 + log 2 )/ (log 3 + log 2 )
beri bilangan pokok 3, maka
= (3log 5 + 3log 2)/(3log 3 + 3log 2)
= ( a +1/b) / (1+ 1/b)
= {( ab+1)/b } / { (b+1)/b}
= (ab+1)/(b+1)