jawab y,khusus yg yakin #matematika minat kls 10

①️
[tex]a.) \: \: p {}^{q} \: = 4 {}^{3 } = 64 \\ b.) \: \: q {}^{p} = 3 {}^{4} = 81 \\ c.) \: \: ( \frac{1}{q} ) {}^{ - p} = ( \frac{1}{3} ) {}^{ - 4} = 3 {}^{4} = 81 \\ d.) \: \: ( \frac{1}{q} ) {}^{ - q} = ( \frac{1}{3} ) {}^{ - 3} = 3 {}^{3} = 9 \\ e.) \: \: ( \frac{1}{p} ) {}^{ - p} = ( \frac{1}{4} ) {}^{ - 4} = 4 {}^{4} = 256[/tex]

Jadi, nilai terbesar yaitu 256. Jawabannya D.


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②️
[tex]( \frac{6a {}^{ - 3} b {}^{2} c {}^{ - 2} }{27a {}^{4}b {}^{ - 1} c {}^{3} } ) {}^{ - 1} \\ = \frac{27a {}^{ 3} b {}^{ - 2} c {}^{ 2} }{6a {}^{ - 4}b {}^{ 1} c {}^{ - 3} } \\ = \frac{27a {}^{3 - ( - 4)} b {}^{ - 2 - 1} c {}^{2 - ( - 3)} }{6} \\ = \frac{27a {}^{3 + 4} b {}^{ - 2 - 1} c {}^{2 + 3} }{6} \\ = \frac{27a {}^{7}b { }^{ - 3} c {}^{5} }{6} \\ = \frac{27a {}^{7} c {}^{5} }{6b {}^{3} } \\ = \frac{9a {}^{7} c {}^{5} }{2b {}^{3} } [/tex]
Jadi, jawabannya D.