( 1/2× + 8/3 )^7× ≤ 2^7×

Kelas 9 Matematika
Bab Akar dan Pangkat

^ = pangkat

((1/2) x + (8/3))^(7x) = 2^(7x)

(1/2) x + (8/3) = 2
(1/2) x = 2 - (8/3)
(1/2) x = 6/3 - 8/3
(1/2) x = -2/3
x = (-2/3) . (2/1)
x = -4/3

Maka, x = 0 dan x = -4/3

Eksponen

(1/2 x + 8/3)^7x ≤ 2^7x
1/2 x + 8/3 ≤ 2
1/2 x ≤ 2 - 8/3
1/2 x ≤ -2/3
x ≤ -4/3

NiLai x yg memenuhi :
x = -4/3 dan x = 0