tolong jawabannya, buat nilai remedial

1. (3a)^(-2) : (2a)^(-5) = (32a^3)/9

2. -7 = 6x - 6
x = -1/6

3. (akar(3) - 3)/(-2)

4. akar 48 + 2(akar 3) - akar 12 = 4(akar 3) + 2(akar 3) - 4(akar 3) = 2(akar 3)