Kak tolong bantu jawab yang no 4 pke cara. Dikumpulinnya bsk makasih

30(2p + 1) ≤ 150
60p + 30 ≤ 150
60p ≤ 120
p ≤ 2

a][
Lebar
= 2p + 1
= 2(2) + 1
= 4 + 1 = 5 m

b][
Biaya keseluruhan
= L x biaya/m²
= (30 x 5)(2.000.000)
= (150)(2.000.000)
= Rp 300.000.000,00

[tex]L = p \times l \\ L = 30 \times (2p + 1) \\ L = 60p + 30 \\ \\ L \leqslant 150 \\ 60p + 30 \leqslant 150 \\ 60p \leqslant 120 \\ p \leqslant 2 [/tex]

■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️

a.)
Lebar tanah Pak Andra paling besar:
[tex]l = 2p + 1 \\l = 2 \times 2 + 1 \\ l = 4 + 1 \\ l = 5 \: m[/tex]

■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️■️

b.)
Biaya maksimal yang dikeluarkan Pak Andra:
[tex]L = p \times l \\ L = 30 \times 5 \\L = 150 \: m {}^{2}[/tex]

1 m² = Rp2.000.000,00
150 m² = ....
[tex]150\times 2.000.000 = Rp300.000.000,00[/tex]