Tentukan Nilai Dari logaritma ³ log9+³log18- ³log2

³log 9 + ³log 18 - ³log 2
= ³log 3² + ³log (9 × 2) - ³log 2
= 2 ³log 3 + ³log 3² + ³log 2 - ³log 2
= 2 (1) + 2 (1)
= 4

[tex] {}^{3} log9 + {}^{3} log18 - {}^{3} log2 \\ = {}^{3} log(9 \times 18 \div 2) \\ = {}^{3} log81 \\ = 4[/tex]