Integral dx/4+(x+1)² ? Mohon Dibantu

[tex]4 + ({x + 1})^{2} \\ = dx \: \: \: \: 4 + ( {x}^{2} + 2x + 1) \\ = dx \: \: \: {x}^{2} + 2x + 5 \\ = { \frac{x}{2 + 1} }^{2 + 1} + { \frac{2x}{2} }^{2} + 5x \\ = { \frac{x}{3} }^{3} + {x}^{2} + 5x[/tex]