titik potong antara parabola y=x2+2×-5 dan garis y= ×+1

y = x² + 2x - 5
y = x + 1

y = y
x² + 2x - 5 = x + 1
x² + x - 6 = 0
(x + 3) (x - 2) = 0
x = -3   x = 2

utk x = -3
y = x + 1
y = -3 + 1
y = -2

utk x = 2
y = x + 1
y = 2 + 1
y = 3

jadi tipot = (-3,-2) dan (2,3)