Ini gimana ya nomor 6 tolong disertakan caranya yaaa.. trimss....

[tex] {2}^{p} = 3 \: \: \: \: \: \: {}^{2} log3 = p \\ {}^{5} log3 = q \\ \\ {}^{15} log720 \\ \frac{ {}^{3} log720 }{ {}^{3} log15 } \\ \frac{ {}^{3} log(5 \times {2}^{4} \times {3}^{2} ) }{ {}^{3} log(3 \times 5) } \\ \frac{ {}^{3} log5 + {}^{3} log{2}^{4} + {}^{3} log {3}^{2} }{ {}^{3} log3 + {}^{3} log5 } \\ \frac{ \frac{1}{ {}^{5} log3 } + 4\frac{1}{ {}^{2} log3 } + 2.1 }{1 + \frac{1}{ {}^{5} log3 } } \\ \frac{ \frac{1}{q} + \frac{4}{p} + 2 }{1 + \frac{1}{q} } \\ \frac{ \frac{p + 4q}{pq} + 2}{ \frac{q + 1}{q} } \\ \frac{ \frac{p + 4q + 2pq}{pq} }{ \frac{q + 1}{q} } \\ \frac{p + 4q + 2pq}{pq} \times \frac{q}{q + 1} \\ \frac{q(p + 4q + 2pq)}{p {q}^{2} + pq } \\ \frac{q(p + 4q + 2pq)}{q(pq + p)} \\ \frac{p + 4q + 2pq}{pq + p} [/tex]