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[tex] \sqrt{32} + \sqrt{18} - 6 \sqrt{2} \\ = \sqrt{16 \times 2} + \sqrt{9 \times 2} - 6 \sqrt{2} \\ = 4 \sqrt{2} + 3 \sqrt{2} - 6 \sqrt{2} \\ = \sqrt{2} [/tex]

jawaban ➡ C.
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[tex] \sqrt{32} + \sqrt{18} - 6 \sqrt{2} \\ = \sqrt{16 \times 2} + \sqrt{9 \times 2} - 6 \sqrt{2} \\ = 4 \sqrt{2} + 3 \sqrt{2} - 6 \sqrt{2} \\ = 1 \sqrt{2} \\ = \sqrt{2} [/tex]