tentukan persamaan kurva y=f(x)jika gradiennya m =dy/dx(x-1)3 dan melalui A(3,0)

jawab

m = y' = (x -1)³
y = ∫ y' dx 
y = ∫ ( x-1)³ dx
y  = 1/4 (x - 1)⁴ + c
melalui (3,0)
0 = 1/4 (3-1)⁴ + c
0 = 1/4(16) + c
0 = 4 + c
c = - 4

y = 1/4 (x + 1)⁴ - 4