Persamaan kuadrat x2-7x-18=0 dgn akar-akar p dan q.jika bilangan asli nilai p-4q=

Persamaan Kuadrat

x² - 7x - 18 = 0
(x - 9)(x + 2) = 0
x = p = 9 atau x = q = -2

p - 4q = 9 - 4(-2) = 9 + 8 = 17

x² - 7x - 18 = 0
( x + 2 )( x - 9 ) = 0
x = - 2 atau x = 9

nilai
p = - 2
q = 9

p - 4q
= - 2 - 4( 9)
= - 2 - 36
= - 38