Matematika

Pertanyaan

2. 3x+4y = 14
x+5y = 12

Dikerjakan dengan tiga cara. yg bisa poin full

2 Jawaban

  • Eliminasi

    3x + 4y = 14 (× 1)
    x + 5y = 12 (× 3)
    3x + ..4y = 14
    3x + 15y = 36
    --------------------- -
    -11y = -22
    y = -22/-11
    y = 2

    3x + 4y = 14 (× 5)
    x + 5y = 12 (× 4)

    15x + 20y = 70
    ..4x + 20y = 48
    ------------------------- -
    11x = 22
    x = 22/11
    x = 2

    jadi HPnya adalah {2 , 2}

    substitusi

    x + 5y = 12
    x = 12 - 5y

    3x + 4y = 14
    3(12 - 5y) + 4y = 14
    36 - 15y + 4y = 14
    36 - 11y = 14
    11y = 36 - 14
    11y = 22
    y = 22/11
    y = 2

    x = 12 - 5y
    x = 12 - 5(2)
    x = 12 - 10
    x = 2

    jadi HPnya adalah {2 , 2}

    campuran

    3x + 4y = 14 (× 1)
    x + 5y = 12 (× 3)

    3x +.. 4y = 14
    3x + 15y = 36
    ---------------------- -
    -11y = -22
    y = -22/-11
    y = 2

    x + 5y = 12
    x + 5(2) = 12
    x + 10 = 12
    x = 12 - 10
    x = 2

    jadi HPnya adalah {2 , 2}
  • tu3x+4y=14 |× 1
    x+5y=12 |×3

    3x+4y=14. metode eliminasi
    3x+15y=36
    ------------------- -
    -11y= -22
    y=-22/-11
    y=2

    3x+4y=14|5
    x+5y=12|4

    15 x+20y=70
    4x+20y=48
    -------------------- -
    11x=22
    x=22/11=2

    x+5y=12
    x= -5y+12

    3x+4y=14
    3(-5y+12)+4y=14
    -15y+36+4y=14. metode substitusi
    -11y+36=14
    -11y=14-36
    -11y=-22
    y=-22/-11
    y=2

    x=-5y+12
    x=-5(2)+12
    x=-10-12
    x=2

    mohon di koreksi

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