gimana caranya no 23,24,25,26 pakem cara ya

semoga membantu yaaaa

23. Bangun Balok → p × l × t
= 4 × 12 × 4 = 192 cm³
Bangun Kubus → s × s × s
= 12 × 12 × 12 = 1.728 cm³
Volume = 192 + 1.728 = 1.920 cm³ (C)
24. L permukaan kerucut → π × r × s
= 22/7×7× [√7²+(⅔×36)²] → bg coret
= 22 × [√7² + 24²]
= 22 × [√49 + 576]
= 22 × [√625]
= 22 × 25 = 550 cm²
L permukaan tabung → alas + selimut
= [π × r²] + [π × d × t]
= [22/7 × 7 × 7] + [22/7 × 14 × (⅓ × 36)] → bgi coret
= [154] × [44 × 12]
= 154 × 528
= 682 cm²
L total = 550 + 682 = 1.232 cm² (A)
25. Volume → alas × t
*bidang trapesium menjadi alas*
= [jumlah sisi sejajar × t / 2] × t
= [(18 + 12) × 12 / 2] × 10
= [30 × 6] × 10
= 180 × 10 = 1.800 cm³ (C)
26. → Volume kardus ÷ volume rubik
= [p × l × t] ÷ [s × s × s]
= [12 × 12 × 18] ÷ [6 × 6 × 6]
= 2.592 ÷ 216
= 12 buah (D)