Matematika

Pertanyaan

tentukan himpunan penyelesaian dari persamaan persamaan logaritma berikut :
A. ^3log (x-5)-^3log(18-2x)=0
B. ^3log(x+4)=^9log(26-x^2)
C. ^3log^2^3logx-8=0

2 Jawaban

  • jawab

    A. 
    3'log (x - 5)  = 3'kog (18-2x)
    x - 5 = 18 - 2x
    3x = 23
    x = 23/3

    B.
    3'log (x + 4) = 9'log (25 - x^2)
    3'log ( x+ 4) = 3'log (25 - x^2 )^(1/2)
    x+ 4 = √(25 - x^2)
    (x+4)² = 25 - x²
    x² + 8x + 16 + x²-25 = 0
    2x² + 8x - 9 = 0
    x²+ 4x -9/2 =0
    x² + 4x  =  9/2
    (x + 2)² = 9/2 + 4 = 17/2
    x + 2 = +- √(17/2)
    x = - 2 + 1/2 √ 34

    c.
    3'log²  (3'log x)  - 8 = 0

    misal 3'log x = a
    3'log² (a) =8
    3'log a = √8
    a = 3^(√8)

    3'log x = a
    x = 3^a
    x = 3^(3^(√8))



  • LogAritMa


    ³log (x - 5) - ³log (18 - 2x) = 0
    x - 5 = 18 - 2x
    x + 2x = 18 + 5
    x = 23/3

    ••
    3'log (x + 4) = 9'log (26 - x²)
    2 . 9'log (x + 4) = 9'log (26 - x²)
    (x + 4)² = 26 - x²
    x² + 8x + 16 + x² - 26 = 0
    2x² + 8x - 10 = 0
    x² + 4x - 5 = 0
    (x + 5)(x - 1) = 0
    x = -5 atau x = 1

    Nilai x yg memenuhi :
    x = 1

    •••
    ³log² (³log x - 8) = 0
    ³log x - 8 = 1
    ³log x = 1 + 8
    x = 3^9

    ^ baca pangkat

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