diketahui penyelesain persamaan

²log² x - ²log x³ = 4
²log² x - 3 ²log x = 4
²log² x - 3 ²log x - 4 = 0
Misal ²log x = a maka diperoleh
a² - 3a - 4 = 0
(a - 4) (a + 1) = 0
a = 4 atau a = -1

a = ²log x
a = 4 »» ²log x = 2⁴ = x = 16
a = -1 »» ²log x = 2-¹ = x = ½

{16, ½}

Ditanyakan nilai x1 . x2 = 16 × ½ = 8