Matematika

Pertanyaan

-sinx+cosx=1 untuk -2π≤x≤2π adalah

1 Jawaban

  • -sin x + cos x = 1
    kuadratkan kedua ruas
    (-sin x + cos x)² = 1²
    sin²x + cos²x - 2.sin x cos x = 1
    1 - 2.sin x cos x = 1
    -2.sin x cos x = 0
    2.sin x cos x = 0
    sin 2x = 0
    sin 2x = sin -4π
    2x = -4π
    x = -4π/2 = -2π
    sin 2x = sin -2π
    2x = -2π
    x = -π
    sin 2x = sin -π
    2x = -π
    x = -½π
    sin 2x = sin 0
    2x = 0
    x = 0
    sin 2x = sin π
    2x = π
    x = ½π
    sin 2x = sin 2π
    2x = 2π
    x = π
    sin 2x = sin 4π
    2x = 4π
    x = 2π
    hp {-2π,-π,-½π,0,½π,π,2π}

Pertanyaan Lainnya