persamaan garis sejajar dengan 2x+4y+9=0 dan melalui titk (-3,4)

2x+4y+9=0
4y = -2x -9
Y = -2/4x -9/4
Y= -½x -9/4
Gradien = -½

Y-Y1 =m(x-x1)
Y-4 = -½(x+3)
Y-4 = -½x -3/2 (dikali2)
2y -8 = -x - 3
2y = -x -3 +8
2y = -x +5
X + 2y -5 = 0

titik (x1,y1) = (-3,4)
M1 = 2x+4y+9=0
4y= -2x-9 -> dibagi 4
y= -1/2x -9/4
M1 = -1/2
*syarat sejajar : M1=M2
-1/2 = M2
*persamaan garis :
y-y1 = M (x-x1)
y-4 = -1/2 (x-(-3))
y-4 = -1/2 (x+3) -> dikali silang
2y-8 = -x -3
2y+x = -3+8
2y+x = 5
2y+x-5 = 0