Mohon bantuannya gan....

(n²+3)
u1=(1²+3)=1+3=4
u2=(2²+3)=4+3=7
u3=(3²+3)=9+3=12
u4=(4²+3)=16+3=19
u5=(5²+3)=25+3=28
u6=(6²+3)=36+3=39
jadi,jumlah 6 suku pertamanya
=(4+7+12+19+28+39)
=(109) jawaban E
#GoodLuck