Tentukan persamaan garis yang melalui titik-titik koordinat berikut! a.A(3,3) dan B(2,1) b.C(-1,4) dan D(1,3) c.E(6,10)dan F(-5,2)

A. Rumus : y-y1/y2-y1 = x-x1/x2-x1

y-3/1-3 = x-3/2-3
y-3/-2 = x-3/-1
-2(x-3) = -1(y-3)
-2x+6 = -1y+3
-2x = -1y+3-6
-2x = -1y-3
atau -2x+1y+3 = 0

B. Rumus : y-y1/y2-y1 = x-x1/x2-x1.

y-4/3-4 = x-(-1)/1-(-1)
y-4/-1 = x+1/2
-1(x+1) = 2(y-4)
-1x-1 = 2y-8
-x = 2y-8+1
-x = 2y-7
atau -x-2y+7 = 0

C. Rumus : y-y1/y2-y1 = x-x1/x2-x1

y-10/2-10 = x-6/-5-6
y-10/-8 = x-6/-11
-8(x-6) = -11(y-10)
-8x+56 = -11y+110
-8x = -11y+110-56
-8x = -11y+54
atau -8x+11y-54 = 0

semoga membantu:)